12n^2-22n-12=-8

Solution for 12n^2-22n-12=-8 equation:

12n^2-22n-12=-8

We move all terms to the left:

12n^2-22n-12-(-8)=0

We add all the numbers together, and all the variables

12n^2-22n-4=0

a = 12; b = -22; c = -4;
Δ = b2-4ac
Δ = -222-4·12·(-4)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-26}{2*12}=\frac{-4}{24}
=-1/6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+26}{2*12}=\frac{48}{24}
=2
$